A 18.5 g bullet is fired from a rifle. It takes 2.70 10-3 s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 660 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.

To find the average net force exerted on the bullet, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:
Mass of the bullet (m) = 18.5 g = 0.0185 kg
Time taken (t) = 2.70 * 10^-3 s
Final velocity (v) = 660 m/s

First, we need to calculate the acceleration (a) of the bullet using the formula:
a = (v - u) / t

Here, the initial velocity (u) is not given, but since the bullet is fired from rest, we can assume the initial velocity to be zero.

By substituting the values into the formula:
a = (660 m/s - 0 m/s) / (2.70 * 10^-3 s)
a ≈ 244,444.44 m/s^2

Now we can calculate the average net force (F) using the formula:
F = m * a

By substituting the values into the formula:
F = 0.0185 kg * 244,444.44 m/s^2
F ≈ 4,518.52 N

Therefore, the average net force exerted on the bullet is approximately 4,518.52 Newtons.

To find the average net force exerted on the bullet, we can use Newton's second law of motion, which states that the net force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a): F = m * a.

In this case, we are given the mass of the bullet (m = 18.5 g = 0.0185 kg) and its acceleration (a). To find the acceleration, we need to use the equation of motion:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. Rearranging the equation, we have:

a = (v - u) / t

Given that the initial velocity (u) of the bullet is zero (since it starts from rest), the final velocity (v) is 660 m/s, and the time taken (t) is 2.70 * 10^-3 s, we can substitute these values into the equation to find the acceleration (a).

a = (660 m/s - 0 m/s) / (2.70 * 10^-3 s)
a = 660000 m/s^2

Now that we have the acceleration, we can substitute it back into the equation F = m * a to find the average net force:

F = (0.0185 kg) * (660000 m/s^2)
F = 12180 N

Therefore, the average net force exerted on the bullet is 12180 Newtons.