An airplane of mass 2800 Kg has just lifted off the runway. It is gaining altitude at a constant 2.3 M/s while the horizontal component of its velocity is increasing at a rate of 0.86 M/s2. Assume g= 9.81 M/s2. (a) Find the direction of the force exerted on the airplane by the air. (b) Find the horizontal and vertical components of the planes acceleration if the force due to the air has the same magnitude but has a direction of 2.0ᴼ closer to the vertical than its description in part (a).

The symbol for meter is m, not capital M.

Force= mass*acceleration
force= mass(.86x+2.3y) a.

direction= arctan2.3/.86