A skateboarder, starting from rest, rolls down a 11.5-m ramp. When she arrives at the bottom of the ramp her speed is 6.95 m/s.
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To find the skateboarder's acceleration, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final velocity (6.95 m/s)
u = initial velocity (0 m/s, since she starts from rest)
a = acceleration (unknown)
s = displacement (11.5 m)
Rearranging the equation, we get:
a = (v^2 - u^2) / (2s)
Substituting the given values, we have:
a = (6.95^2 - 0^2) / (2 * 11.5)
a = 48.2025 / 23
a ≈ 2.1 m/s^2
Therefore, the skateboarder's acceleration is approximately 2.1 m/s^2.