a car traveling 7.0 m/s accelerates uniformly at 2.5 m/s squared to reach a speed of 12 m/s. how long does it take for the acceleration to occur?

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2.0 s

To find out how long it takes for the acceleration to occur, we can use the equation of motion:

\(v = u + at\)

where:
v = final velocity
u = initial velocity
a = acceleration
t = time

In this case, the initial velocity (u) is 7.0 m/s, the final velocity (v) is 12 m/s, and the acceleration (a) is 2.5 m/s^2.

Using the equation, we can rearrange it to solve for time (t):

\(t = \frac{{v - u}}{{a}}\)

Substituting the given values into the equation:

\(t = \frac{{12 - 7.0}}{{2.5}}\)

Calculating the above expression:

\(t = \frac{{5.0}}{{2.5}}\)

\(t = 2.0\) seconds

Therefore, it takes 2.0 seconds for the acceleration to occur.

To find the time it takes for the acceleration to occur, we can use the equation:

v = u + at

Where:
v = final velocity (12 m/s)
u = initial velocity (7.0 m/s)
a = acceleration (2.5 m/s^2)
t = time

Rearranging the equation to solve for time (t):

t = (v - u) / a

Substituting the given values into the equation:

t = (12 m/s - 7.0 m/s) / 2.5 m/s^2

Now we can calculate the time it takes for the acceleration:

t = 5.0 m/s / 2.5 m/s^2

t = 2.0 seconds

So, it takes 2.0 seconds for the car to accelerate to a speed of 12 m/s.