An airplane has a velocity relative to the air of 192 m/s in the westerly direction. If the wind has a speed relative to the ground of 59 m/s directed to the north, what is the speed of the plane relative to the ground?
It is the magnitude of the vector sum of the plane velocity relative to the air, and the wind velocity.
Since the two velocities you are adding are perpendicular, you can use the pythagorean theorem for the magnitude of the resultant.
sqrt[(192)^2 + (59)^2] = ___ m/sposted by drwls
200.86posted by Anonymous