A helicopter is rising at 5.2 m/s when a bag of its cargo is dropped. The bag falls for 2.5 s. what is the bags velocity
To find the velocity of the bag when it falls, you can use the equation of motion:
v = u + gt
Where:
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time
In this case, the bag is dropped, so its initial velocity, u, is 0 m/s.
We are given that the bag falls for 2.5 seconds, so we can substitute these values into the equation:
v = 0 + (9.8 m/s^2)(2.5 s)
Calculating the right-hand side of the equation:
v = 0 + 24.5 m/s
Therefore, the bag's velocity is 24.5 m/s downward.