Substance A has a specific heat of .650J/gK and substance B has a specific heat of .325J/gK. If 100 J of energy is applied to a 10 g sample of each substance, which will have a higher temperature?
Work it out.
q = mass x specific heat x delta T.
To determine which substance will have a higher temperature, we need to calculate the change in temperature for each substance using their specific heat capacities.
The formula to calculate the change in temperature is:
ΔT = Q / (m * c)
Where:
ΔT is the change in temperature
Q is the amount of energy applied
m is the mass of the substance
c is the specific heat capacity of the substance
Let's first calculate the change in temperature for substance A:
ΔT_A = Q / (m * c_A)
ΔT_A = 100 J / (10 g * 0.650 J/gK)
ΔT_A = 100 J / 6.5 J/K
ΔT_A ≈ 15.38 K
Now let's calculate the change in temperature for substance B:
ΔT_B = Q / (m * c_B)
ΔT_B = 100 J / (10 g * 0.325 J/gK)
ΔT_B = 100 J / 3.25 J/K
ΔT_B ≈ 30.77 K
Comparing the two values, we can see that substance B will have a higher change in temperature. Therefore, substance B will have a higher final temperature.