If you have the terms 64, 49, 36, 25, 16, 9, 5, and 1 what equation will work to find the nth term?
so first you do 64-49 to see what's the difference. Then you have 15 so you need to subtract 15 every time and then you write 15 times table under the numbers and see what's the difference. And you write 15n-(the difference between the numbers from the time table. More precisely write 'how to find the nth term in a sequence in youtube and you will see its easier and I don't even know why are you asking here you can just write in youtube its sos stupid to waste your time write it here
To find the equation that determines the nth term of a sequence, we can observe that the given sequence starts with 64 and continuously decreases by a square number (starting from 7^2 = 49, then 6^2 = 36, and so on). However, there is a change in pattern when we reach the term 5. From 16 to 9, the sequence seems to decrease by 7, and then from 9 to 5, it seems to decrease by 4.
Based on these observations, we can break down the sequence into two parts:
1. The terms 64, 49, 36, 25 form a decreasing sequence of perfect squares. We can write this part of the sequence using the equation: a(n) = (8 - n)^2, where n represents the position of the term in the sequence.
2. The terms 16, 9, 5 indicate a decreasing pattern, where each term is decreasing by 7, then 4 successively. To incorporate this pattern into our equation, we notice that the difference between 16 and 9 is 7, and the difference between 9 and 5 is -4. This suggests that we need to start subtracting 7, then switch to subtracting 4 when we reach the term 9. To achieve this, we can create a piecewise function where the formula changes after the term 9. Let's use the equation: a(n) = 16 - [(n > 5) * 7] - [(n > 7) * 4].
By combining the two parts, the final equation to find the nth term of the given sequence would be:
a(n) = (8 - n)^2 + [16 - (n > 5) * 7 - (n > 7) * 4].