statistics

once again I am not getting this.
assume that the population of heights of male college students is normally distibuted with a mean of 69.09 and standard deviation of 4.71. A random sample of 92 heights is obtained. find the mean and standard error of the x distribution.
find P(x>68.5)

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  1. SEm = SD/√n

    Best guess at the mean is the population mean.

    Z = (score-mean)/SEm

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion (P) related to the Z score.

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