An object measures 12 x 3 x 2.5 cm and has a density of 0.6 g/cm3. When it is placed in water, what is the volume of the part of the object that is above the surface of the water?
To find the volume of the part of the object that is above the surface of the water, we need to determine the volume of the whole object and then subtract the volume of the part submerged in water.
Step 1: Calculate the volume of the object.
The object measures 12 x 3 x 2.5 cm, so its volume can be determined by multiplying these dimensions: 12 cm * 3 cm * 2.5 cm = 90 cm³.
Step 2: Determine the volume of the part submerged in water.
To determine the volume of the part of the object that is submerged in water, we need to determine how much water the object displaces. Since the object is submerged, it displaces an amount of water equivalent to its volume.
The density of the object is given as 0.6 g/cm³, which means that each cubic centimeter of the object has a mass of 0.6 grams. We need to find the mass of the object.
Step 3: Calculate the mass of the object.
The mass of the object can be determined using the formula: Mass = Density * Volume.
Given the density as 0.6 g/cm³ and the volume as 90 cm³, we can calculate the mass: Mass = 0.6 g/cm³ * 90 cm³ = 54 grams.
Step 4: Calculate the volume of water displaced.
Since the object displaces its own volume in water, the volume of water displaced is equal to the volume of the object, which we obtained as 90 cm³.
Step 5: Calculate the volume of the part above the water surface.
The volume of the part above the water surface can be found by subtracting the volume of water displaced from the total volume of the object: Volume above water = Total volume - Volume of water displaced.
Volume above water = 90 cm³ - 90 cm³ = 0 cm³.
The volume of the part of the object that is above the surface of the water is 0 cm³.