Bao Xishun is the world's tallest man with a hieght of 92.95 in. (or 7ft, 8.96 in.). men have hieghts witha mean of 69.6in and a standard deviation of 2.8 in.
1) convert Boa's height to a z score
2) does Boa's height meet the criterion of being unusual by corresponding to a z score that does not fall between -2 and 2?
Use z-score formula to find z-score:
z = (x - mean)/sd
x = 92.95
mean = 69.6
sd = 2.8
I'll let you take it from here.
8.34
To convert Bao Xishun's height to a z-score, you need to use the formula:
z = (x - μ) / σ
Where:
- z is the z-score
- x is the value you want to convert (Bao Xishun's height in this case)
- μ is the mean of the population
- σ is the standard deviation of the population
1) To find the z-score for Bao Xishun's height:
z = (92.95 - 69.6) / 2.8
z = 23.35 / 2.8
z ≈ 8.34
So, Bao Xishun's height has a z-score of approximately 8.34.
2) To determine whether Bao Xishun's height is considered unusual, we need to compare the z-score to the range typically used, which is -2 to 2.
Since Bao Xishun's z-score of 8.34 is outside the range of -2 to 2, his height can be considered as unusual.