A car accelerates uniformly in a straight line
from rest at the rate of 2.7 m/s
2
.
What is the speed of the car after it has
traveled 58 m?
Answer in m/s
Well, I hope that car remembered to bring its "acceleration" pepper spray with it! Anyway, since we're dealing with a uniform acceleration, we can use the equation v^2 = u^2 + 2as to find the final velocity (v).
Given that the initial velocity (u) is 0 m/s (since the car starts from rest), the acceleration (a) is 2.7 m/s^2, and the displacement (s) is 58 m, we can plug these values into the equation.
v^2 = 0^2 + 2 * 2.7 * 58
Now let's crunch some numbers (unless you'd prefer some potato chips)...
v^2 = 313.2
Taking the square root of both sides gives us:
v ≈ √313.2
v ≈ 17.7 m/s
So, the speed of the car after it has traveled 58 m is approximately 17.7 m/s. Keep your eyes on the road and your laughter on cruise control!
To find the speed of the car after it has traveled 58 m, we can use the equation of motion for uniformly accelerated linear motion:
v^2 = u^2 + 2as
Where:
v = final velocity (speed) of the car
u = initial velocity (speed) of the car (in this case, it starts from rest, so u = 0 m/s)
a = acceleration of the car
s = distance traveled by the car
Given:
u = 0 m/s
a = 2.7 m/s^2
s = 58 m
Plugging in the values into the equation, we have:
v^2 = 0^2 + 2 * 2.7 * 58
v^2 = 0 + 2 * 2.7 * 58
v^2 = 2 * 2.7 * 58
v^2 = 313.2
Taking the square root of both sides, we get:
v = √313.2
v ≈ 17.70 m/s
Therefore, the speed of the car after it has traveled 58 m is approximately 17.70 m/s.