The combustion of 1.0 of gasoline releases 11 of heat (density of gasoline = 0.74 ). How many megajoules are released when 1.5 of gasoline burns?
You can't work problems without units. 11 WHAT? 0.74 WHAT? etc.
To calculate the number of megajoules released when 1.5 liters of gasoline burns, we need to use the given value of heat released per liter and the density of gasoline.
Step 1: Calculate the mass of gasoline
Given volume of gasoline = 1.5 L
Density of gasoline = 0.74 g/mL
Density = Mass / Volume
Rearranging the equation, we have:
Mass = Density x Volume
Mass = 0.74 g/mL x 1.5 L
Step 2: Convert grams to kilograms
To convert grams to kilograms, divide the mass by 1000.
Mass = (0.74 g/mL x 1.5 L) / 1000
Step 3: Calculate the heat released for 1.5 L of gasoline
Given heat released per liter of gasoline = 11 MJ/L
Heat released = (Heat released per liter) x (Volume of gasoline)
Heat released = 11 MJ/L x 1.5 L
Step 4: Calculate the number of megajoules released
To convert joules to megajoules, divide the heat released by 1,000,000.
Megajoules released = (Heat released for 1.5 L) / 1,000,000
Now, we can substitute the values into the equation:
Megajoules released = (11 MJ/L x 1.5 L) / 1,000,000
Simplifying the expression:
Megajoules released = 0.0165 MJ
Therefore, when 1.5 liters of gasoline burns, approximately 0.0165 MJ of heat is released.