What is the maximum mass of S8 that can be produced by combining 92.0g of reactant?
8SO2 + 16H2S -> 2S8 + 16H2O
See your duplicate post above.
122
To find the maximum mass of S8 that can be produced, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed.
To calculate the limiting reactant, we will compare the number of moles of each reactant to the stoichiometric ratio in the balanced equation.
Step 1: Calculate the number of moles for each reactant:
First, we need to convert the mass of the reactant given (92.0g) into moles. To do this, we divide the mass by the molar mass of the substance.
Molar mass of 8SO2: (32.06 g/mol x 8) + (16.00 g/mol x 2) = 272.26 g/mol
Moles of 8SO2 = 92.0 g / 272.26 g/mol = 0.338 mol
Molar mass of 16H2S: (1.008 g/mol x 2) + (32.06 g/mol x 16) = 513.78 g/mol
Moles of 16H2S = 92.0 g / 513.78 g/mol = 0.179 mol
Step 2: Determine the limiting reactant:
Next, we compare the mole ratios of each reactant to the stoichiometric ratio in the balanced equation. The balanced equation tells us that for every 8 moles of 8SO2, we produce 2 moles of S8. For every 16 moles of 16H2S, we produce 2 moles of S8.
Comparing the mole ratios:
8SO2: S8 = 8:2
16H2S: S8 = 16:2
Since the mole ratio of 8SO2 to S8 is 8:2 (or simplified, 4:1), and the mole ratio of 16H2S to S8 is 16:2 (or simplified, 8:1), we can see that 8SO2 is the limiting reactant because it has a lower ratio with S8 than 16H2S.
Step 3: Calculate the mass of S8 produced:
Now that we know that 8SO2 is the limiting reactant, we can calculate the maximum moles of S8 produced.
From the balanced equation, we know that 8 moles of 8SO2 produce 2 moles of S8.
Moles of S8 = (0.338 mol 8SO2) * (2 mol S8 / 8 mol 8SO2) = 0.0845 mol S8
The molar mass of S8 is 256.48 g/mol. Therefore, we can calculate the mass of S8 produced:
Mass of S8 = (0.0845 mol S8) * (256.48 g/mol) = 21.67 g
Therefore, the maximum mass of S8 that can be produced by combining 92.0g of the reactant is 21.67 grams.