A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. Assume the plane is traveling horizontally with a speed of 195 km/h (54.2 m/s).
How far in advance of the recipients (horizontal distance) must the goods be dropped
time to fall
235 = .5 g t^2 = 4.9 t^2
so t = 6.93 seconds
horizontal distance = 54.2*6.93
posted by Damon