Physics

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. Assume the plane is traveling horizontally with a speed of 195 km/h (54.2 m/s).
How far in advance of the recipients (horizontal distance) must the goods be dropped

asked by Bridge
  1. time to fall
    235 = .5 g t^2 = 4.9 t^2
    so t = 6.93 seconds
    horizontal distance = 54.2*6.93

    posted by Damon

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