A bus is pushed forward and released at = 3.5 with a speed of 1.0 . It rolls at a steady speed for 1.2 , then one wheel begins to stick. The bus comes to a stop 3.4 from the point at which it was released.
To determine the acceleration of the bus, we can use the kinematic equation:
v² = u² + 2as
Where:
v is the final velocity (zero, since the bus comes to a stop)
u is the initial velocity (1.0 m/s)
a is the acceleration
s is the displacement (3.4 m)
Rearranging the formula to solve for acceleration (a), we have:
a = (v² - u²) / 2s
Substituting the values into the equation:
a = (0 - 1.0²) / (2 * 3.4)
= -1.0 / 6.8
= -0.147 m/s²
Therefore, the acceleration of the bus when the wheel starts sticking is approximately -0.147 m/s² (negative value indicating deceleration).