A point charge of -8.4 µC is at the origin.
a)What is the electric potential due to this charge at (x,y) = (3.5 m, 0 m)
b) What is the electric potential due to this charge at (x,y) = (-3.5 m, 0 m)
c) What is the electric potential to this charge at (x,y) =(3.5 m, -3.5 m)?
For a & b i got -2.1600e4 then Distance between q & the given point, d = v2 * 3.5 m...what is v2 so that i can figure out the distance for part c?
To find the electric potential due to a point charge at a given point, you can use the equation:
V = k * (q / r)
where V is the electric potential, k is the Coulomb's constant (8.99 × 10^9 N m^2 / C^2), q is the charge of the point charge, and r is the distance between the point charge and the given point.
a) To find the electric potential at (3.5 m, 0 m), you have already calculated it as -2.1600e4. The distance between the point charge at the origin and the given point is 3.5 m.
b) Similarly, to find the electric potential at (-3.5 m, 0 m), you can use the same equation as in part a. The distance between the point charge at the origin and the given point is also 3.5 m. The calculation should lead you to the same result as in part a.
c) To find the electric potential at (3.5 m, -3.5 m), you need to calculate the distance between the point charge at the origin and the given point. The distance formula in this case is:
d = √((x2 - x1)^2 + (y2 - y1)^2)
where (x1, y1) represents the coordinates of the point charge at the origin (0, 0), and (x2, y2) represents the coordinates of the given point (3.5 m, -3.5 m). Plugging in the values, you get:
d = √((3.5 m - 0 m)^2 + (-3.5 m - 0 m)^2)
Simplifying the equation:
d = √(3.5^2 + (-3.5)^2)
Once you calculate the distance, you can use the electric potential formula mentioned above (V = k * (q / r)) to find the electric potential at (3.5 m, -3.5 m) by again plugging in the charge and the distance into the equation.