physics 8b

A piece of wire with mass per unit length 88 g/m runs horizontally at right angles to a horizontal magnetic field. A 6.5A current in the wire results in its being suspended against gravity.
What is the magnetic field strength?
B = T

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1. force= mg= ILB
mg/IL = B

m/L is given as .088kg/meter
g is well known
I is given.

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bobpursley
2. Use the equation F=IL X B that relates force on a current in a magnetic field.

Knowing the mass of the wire (.08)kg and the acceleration due to grav (9.8m/s^2) relate the two forces and solve for the variable B.

Because the cross product of L and B is 1 the relation is pretty simple.

(9.8)(.08)=5.8B

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