a student measures the velocity of a water in a stream as 2.5 meters pe second.the actual velocity of the water is 3.0 meters per second. what is the approximate percent deviation of the studen's measurement
17%
.500
To find the approximate percent deviation of the student's measurement, we first need to calculate the absolute difference between the student's measured velocity and the actual velocity:
Absolute Difference = |Actual Velocity - Measured Velocity|
Absolute Difference = |3.0 m/s - 2.5 m/s|
Absolute Difference = 0.5 m/s
Next, we need to calculate the percent deviation using the formula:
Percent Deviation = (Absolute Difference / Actual Velocity) * 100%
Percent Deviation = (0.5 m/s / 3.0 m/s) * 100%
Percent Deviation ≈ 0.1667 * 100%
Percent Deviation ≈ 16.67%
Therefore, the approximate percent deviation of the student's measurement is approximately 16.67%.