When I am rounded to the nearest 10, I am 80. The sum of the two digits is 15. What number am I?
75, 76, 77, 78, 79, 81, 82, 83, 84
Which of those numbers have digits that add up to 15?
when i am rounded to the nearest hundred, i am 400. The digit in my tens place is 4 more than the digit in my hundreds place. the digits in my hundreds place and ones place are the same. what number am i?
To find the number that is rounded to the nearest 10 at 80 and has a sum of digits equal to 15, we can follow these steps:
1. Let's assume the unknown number is represented by two digits: tens digit (x) and ones digit (y). So, the number can be written as 10x + y.
2. Since the number is rounded to the nearest 10 and is 80, it must be between 75 and 85. Therefore, the tens digit (x) can only be 7 or 8.
3. Now, we know that the sum of the two digits is 15. So, we can set up the equation x + y = 15.
4. Let's substitute the possible values for x in the equation to find y:
- When x = 7, 7 + y = 15, y = 15 - 7, y = 8.
- When x = 8, 8 + y = 15, y = 15 - 8, y = 7.
5. Now we have two potential numbers: 78 and 87.
6. However, we need to check which one of these numbers rounds to 80 when rounded to the nearest 10. Rounding 78 to the nearest 10 gives 80, while rounding 87 gives 90.
7. Therefore, the number is 78.
So, the number you are is 78.