Let M=1000. Which of the conditions is equivalent to f(x)= 1/((4x-12)^2)>M?
a. absolute value of (x+3) is greater than or equal to .00158
b. absolute value of (x+3) is greater than or equal to .0553
c. absolute value of (x-3) is less than .00791
d. absolute value of (x-3) is less than .00158
e. absolute value of (x) is greater than .00395
We have
1/(4x-12)^2 = 1/16(x-3)^2 > 1000
(x-3)^2 < 1/16000
|x-3| < 0.00791