a uniformly accelerating train passes a green light signal at25.0 km/hr it passes a second light 125m farther down the track 12.0s later what is the trains acceleration? what is the trains velocity at the second light?

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  1. x = Vi t + (1/2) a t^2

    125 = (25000/3600)(12) + .5 * a * 144
    solve for a

    v = Vi + a t

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  2. where did you get the 144

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  3. ok i get

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  4. correct me if im wrong solve for a = 102
    and v = 1249

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  5. A = 51.15
    V= 638.8

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