# physics

a uniformly accelerating train passes a green light signal at25.0 km/hr it passes a second light 125m farther down the track 12.0s later what is the trains acceleration? what is the trains velocity at the second light?

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1. x = Vi t + (1/2) a t^2

125 = (25000/3600)(12) + .5 * a * 144
solve for a

then
v = Vi + a t

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2. where did you get the 144

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3. ok i get

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4. correct me if im wrong solve for a = 102
and v = 1249

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5. A = 51.15
V= 638.8

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