If you used the 8900 kilojoules you expend in energy in one day to heat 46000 {\rm g} of water at 25^\circ {\rm C}, what would be the rise in temperature?

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  1. q = mass water x specific heat water x delta T. Solve for delta T. Add 25 if you want to know the final T.

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  2. 0.015

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