I need help with finding an equation to a line.
Its finding an equation with the intercepts x=-1 and y=3.
Ive gotten the slope of -3 but i don't know where to go from there......
The x-intercept are where the graph crosses the x-axis, and the y-intercept are where the graph crosses the y-axis.
an x-intercept is a point in the equation where the y-value is zero,
and
a y-intercept is a point in the equation where the x-value is zero.
x-intercept:
x = -1 and y = 0
y-intercept:
x = 0 y = 3
Two-point form of the linear equation:
y - y1 = [( y2 - y1 ) / ( x2 - x1 ) ] * ( x - x1 )
where (x1,y1) and (x2,y2) are two points on the line with x2 �‚ x1.
In this case:
x1 = - 1
y1 = 0
x2 =0
y2 = 3
So:
y - y1 = [( y2 - y1 ) / ( x2 - x1 ) ] * ( x - x1 )
y - 0 = [( 3 - 0 ) / ( 0 - ( -1 ) ] * ( x - ( - 1 )
y = ( 3 / 1 ) * ( x + 1)
y = 3 * ( x + 1 )
y = 3x + 3
x+2y+z=1
-x+y+2=6
4x-y+3z=-1
To find the equation of a line when given the x-intercept and y-intercept, you can use the slope-intercept form of a linear equation, which is:
y = mx + b
In this equation, 'm' represents the slope of the line, and 'b' represents the y-intercept.
Given that you have a slope of -3, you can substitute this value into the equation:
y = -3x + b
To determine the value of 'b', you need to use one of the intercepts provided. In this case, let's use the y-intercept of 3. Substitute the value of y = 3 and x = 0 (since the y-intercept occurs when x = 0) into the equation:
3 = -3(0) + b
Simplifying, you find:
3 = b
Now that you have the value of 'b', substitute it back into the equation:
y = -3x + 3
Therefore, the equation of the line with x-intercept = -1 and y-intercept = 3 is:
y = -3x + 3