How many molecules of NH3 could be generated from 64 molecules of N2 and 210 molecules of H2? How many molecules of N2 and H2 would be left over after the reaction?
To determine the number of molecules of NH3 that can be generated from the given number of molecules of N2 and H2, we first need to balance the chemical equation for the reaction between N2 and H2 to form NH3.
The balanced chemical equation for the reaction is:
N2 + 3H2 -> 2NH3
From the balanced chemical equation, we can see that 1 molecule of N2 reacts with 3 molecules of H2 to produce 2 molecules of NH3.
Now let's calculate the number of NH3 molecules that can be generated:
1. Start with the given number of N2 molecules: 64 molecules
2. Convert the number of N2 molecules to the number of NH3 molecules using the stoichiometry of the reaction:
64 molecules N2 * (2 molecules NH3 / 1 molecule N2) = 128 molecules NH3
So, 128 molecules of NH3 can be generated from 64 molecules of N2.
Next, let's determine the number of N2 and H2 molecules that would be left over after the reaction.
1. Calculate the used N2 molecules:
Number of N2 molecules used = 64 molecules N2 - 64 molecules N2 used in the reaction
Number of N2 molecules used = 64 - (2 NH3 produced / 1 N2 used) = 64 - (2 * 64 / 1) = 64 - 128 = -64
Since we end up with a negative number of N2 molecules, it means that all the N2 molecules have been used in the reaction, and there will be no N2 molecules left over.
2. Calculate the used H2 molecules:
Number of H2 molecules used = 210 molecules H2 - (3 molecules H2 used per 2 NH3 produced) * (128 NH3 produced / 2 NH3 used)
Number of H2 molecules used = 210 - (3 * 128 / 2) = 210 - 192 = 18 molecules
Therefore, after the reaction, there will be:
- 128 molecules of NH3 generated
- No molecules of N2 left over
- 18 molecules of H2 left over.