a moving sidewalk in an airport terminal building moves 1.00 m/s and is 150.0 m long.If man steps on at one end and walks 2.0 m/s relative to the moving sidewalk, how much time does he require to reach the opposite end if he walks in the same directions as the side walk is moving?

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  1. v=1.00m/s + 2.0m/s = 3.0 m/s
    t = 150.0m/3.0 m/s = 50s

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  2. to get time, you use the formula X=Xo+Vot+1/2at^2 where X=150

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