The organizers of of a walkathon get cost estimates from two printing companies to print brochures to advertise the event. The cost are given by the equations below, were C is the cost in dollars and N is the number of brochures.

Company A: C = 15 + 0.10n
Company B: C = 0.25n
A: for what number of brochures are the costs the same for both companies? What method did you use to get your answer? B: The organizers have 65$ to spend on brochures. How many brochures can they have printed if they used company A? If they use company B? C

A. 15+.1n = .25n

B. 65 = 15 + .1n

C. 65 = .25n

(Solve for n.)

what information does the coeffecient of n represent for each equation

A: To find the number of brochures at which the costs are the same for both companies, we can set the two cost equations equal to each other and solve for n:

15 + 0.10n = 0.25n

Simplifying the equation:

15 = 0.25n - 0.10n

15 = 0.15n

Dividing both sides by 0.15:

n = 15 / 0.15

n = 100

Therefore, the costs will be the same for both companies when 100 brochures are printed.

I used the method of setting the two cost equations equal to each other and solving for n to find the number of brochures at which the costs are the same.

B:

If the organizers have $65 to spend on brochures, we can substitute this value into the cost equations to find how many brochures they can have printed for each company.

For Company A:

C = 15 + 0.10n

65 = 15 + 0.10n

Subtracting 15 from both sides:

50 = 0.10n

Dividing both sides by 0.10:

n = 50 / 0.10

n = 500

Therefore, if the organizers use company A, they can have 500 brochures printed with $65.

For Company B:

C = 0.25n

65 = 0.25n

Dividing both sides by 0.25:

n = 65 / 0.25

n = 260

Therefore, if the organizers use company B, they can have 260 brochures printed with $65.

A: To find the number of brochures for which the costs are the same for both companies, we need to set the equations for Company A and Company B equal to each other and solve for n.

First, let's set up the equation:
C(A) = C(B)

From the given equations:
15 + 0.10n = 0.25n

Now, solve for n:
15 = 0.15n
n = 15 / 0.15
n = 100

Therefore, the costs will be the same for both companies when 100 brochures are printed.

To find the answer, I used the method of setting the costs of both companies equal to each other and then solving for the number of brochures.

B: Now, let's find out how many brochures the organizers can have printed with $65 using each company.

For Company A:
We have the equation:
C(A) = 15 + 0.10n

We need to find the value of n for which C(A) is less than or equal to $65:
15 + 0.10n ≤ 65

Now solve for n:
0.10n ≤ 65 - 15
0.10n ≤ 50
n ≤ 50 / 0.10
n ≤ 500

Therefore, if the organizers use Company A, they can have a maximum of 500 brochures printed with $65.

For Company B:
We have the equation:
C(B) = 0.25n

We need to find the value of n for which C(B) is less than or equal to $65:
0.25n ≤ 65

Now solve for n:
n ≤ 65 / 0.25
n ≤ 260

Therefore, if the organizers use Company B, they can have a maximum of 260 brochures printed with $65.