physics

If a stone is thrown upward at 20.5 m/s, what will be its velocity at a height of 12 meters?

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  1. Kinetic energy at start = (1/2)m(20.5)^2

    Kinetic energy at 12 meters = (1/2) m v^2

    so

    (1/2) m v^2 = (1/2) m (20.5)^2 - m g (12)

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