Hexane has a density of 0.659 g/ml. How many milliliters (mL) would a student need to pour in order to get 49.5 g of hexane?
75.1 mL
mass = volume x density.
Substitute and solve for mL.
Hexane has a density of 0.659 g/ml. How many milliliters (mL) would a student need to pour in order to get 49.5 g of hexane?
To find the number of milliliters (mL) needed to get 49.5 g of hexane, we can use the equation:
Density = Mass / Volume
Rearranging this equation, we can say:
Volume = Mass / Density
Now, we can substitute the known values into the equation:
Mass = 49.5 g
Density = 0.659 g/ml
Plugging in these values, we get:
Volume = 49.5 g / 0.659 g/ml
To find the volume, simply divide 49.5 g by 0.659 g/ml:
Volume = 75.12 ml
Therefore, a student would need to pour approximately 75.12 milliliters (mL) of hexane to obtain 49.5 grams of the substance.