Hexane has a density of 0.659 g/ml. How many milliliters (mL) would a student need to pour in order to get 49.5 g of hexane?

75.1 mL

mass = volume x density.

Substitute and solve for mL.

Hexane has a density of 0.659 g/ml. How many milliliters (mL) would a student need to pour in order to get 49.5 g of hexane?

To find the number of milliliters (mL) needed to get 49.5 g of hexane, we can use the equation:

Density = Mass / Volume

Rearranging this equation, we can say:

Volume = Mass / Density

Now, we can substitute the known values into the equation:

Mass = 49.5 g
Density = 0.659 g/ml

Plugging in these values, we get:

Volume = 49.5 g / 0.659 g/ml

To find the volume, simply divide 49.5 g by 0.659 g/ml:

Volume = 75.12 ml

Therefore, a student would need to pour approximately 75.12 milliliters (mL) of hexane to obtain 49.5 grams of the substance.