if the unit of power is the watt (W), and P = Fd/t, show using the result of question (2) and the fact that distance (d) uses units of meters and time has units of seconds.

*** question 2. If m represents mass in kg, v represents speed in m/s, and r represents radius in m, show that the force F in the question F = mv^2/r can be expressed in the unit kgm/s^2.

F=mv^2/r -----> kg(m/s)^2/m ---> kgm^2s^2/m = kgms^2

you have an error.

F=mv^2/r -----> kg(m/s)^2/m --->
kgm^2 /s^2 m = kgm/s^2

To show the relationship between the unit of power, the watt (W), and the equation P = Fd/t, we need to substitute the expression for force, F, in terms of mass, velocity, and radius into this equation.

From question (2), we know that force, F, is given by F = mv^2/r. Now, let's substitute this expression into the power equation:

P = Fd/t

Replacing F with mv^2/r, we have:

P = (mv^2/r)d/t

Now, since distance, d, is measured in meters and time, t, in seconds, we can simplify the equation further:

P = (m * (m/s)^2 / r) * d/s

Simplifying the units of speed squared:

P = (m * m^2/s^2 / r) * d/s

Multiplying the units:

P = (m * m^2 * d) / (r * s^3)

We can rearrange this equation to group similar units together:

P = (m * d * m^2) / (r * s^3)

Rearranging further:

P = (m^3 * d) / (r * s^3)

Finally, remembering that m^3/s^3 is equal to the unit of power, the watt (W), we have:

P = W * d / r

So, we see that the power P measured in watts is given by the expression W * d / r, where distance, d, is in meters and time, t, is in seconds.

Therefore, by using the result of question (2) and considering the units of distance and time, we have shown the relationship between the unit of power, the watt (W), and the equation P = Fd/t.