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physics

a ball is thrown up with an initial velocity 20m/s. using g=10m/s2,
a) what's the maximum height it can reach.
b) what is the magnitude and direction of the ball's velocity 1 second after it is thrown.
c) what is the magnitude and direction of the ball's velocity 3 seconds after it is thrown

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asked by jennifer

  1. a. h = (Vf^2 - Vo^2) / 2g,
    h = (0 - (20)^2) / 20 = 20m.

    b. Vf = Vo + gt,
    Vf = 20 + (-10)*1 = 10m/s,up.

    c. Vf = 20 + (-10)*3 = -10m/s,down.

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    posted by Henry

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