Chem

If 0.03 moles of sulfuric acid is mixed
with water to make 266 mililiter of solution, what is the molarity of H+?
Answer in units of M.

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  1. How advanced is this course? This isn't the simple problem it appears.
    M H2SO4 = moles/L = 0.03/0.266 = ??
    H2SO4 ==> H^+ + HSO4^-
    0.113M...0.113...0.113

    HSO4^- ==> H^+ + SO4^2-
    0.113-x....x......x

    k2 for H2SO4 = about 0.012 = (H^+)(SO4^2-)/(HSO4^-)
    Substitute into k2 expression and solve for x. I get 0.01 for x which means H^+ = 0.123M (not twice the molarity as one might think).
    You should confirm k2 and all of the work. The k2 expression evolves into a quadratic OR you may solve it by iteration.

    H2SO4 ==> H^+ + HSO4^-

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