How many milliliters of 1.4 M HCl must be
transfered from a reagent bottle to provide
23 g HCl for a reaction?
Answer in units of mL
mass= molarity*molmass*volume
= 1.4M*36.5*V
solve for V in liters.
To solve this problem, we need to use the concept of molarity, which is defined as the number of moles of solute per liter of solution.
First, we need to calculate the number of moles of HCl required for the reaction using the given mass. The molar mass of HCl is 36.46 g/mol.
Number of moles of HCl = Mass / Molar mass
= 23 g / 36.46 g/mol
= 0.631 mol
Next, we use the molarity to calculate the volume of the 1.4 M HCl solution required.
Molarity = Number of moles / Volume in liters
Rearranging the equation, we get:
Volume in liters = Number of moles / Molarity
Volume in liters = 0.631 mol / 1.4 M
= 0.451 L
Finally, we convert the volume from liters to milliliters.
Volume in mL = Volume in liters × 1000
= 0.451 L × 1000
= 451 mL
Therefore, you need to transfer 451 mL of 1.4 M HCl from the reagent bottle to provide 23 g HCl for the reaction.