Sue and Jenny kick a soccer ball at exactly

the same time. Sue’s foot exerts a force of
56.6 N to the north. Jenny’s foot exerts a
force of 88.6 N to the east.

a) What is the magnitude of the resultant
force on the ball?
Answer in units of N

b) What is the direction of the resultant force
(measured from East)?
Answer in units of �degrees

I will be happy to critique your thinking or work on this.

I am lost on it

Its 90 newtons

To find the magnitude and direction of the resultant force on the soccer ball, we can use vector addition. We need to add the forces exerted by Sue and Jenny as vectors.

a) Magnitude of the resultant force:
To find the magnitude of the resultant force, we can use the Pythagorean theorem. The magnitude of the resultant force is the square root of the sum of the squares of the individual forces.

Magnitude of Sue's force (FSue) = 56.6 N
Magnitude of Jenny's force (FJenny) = 88.6 N

Using the Pythagorean theorem:
Magnitude of the resultant force (FR) = sqrt(FSue^2 + FJenny^2)

Therefore, the magnitude of the resultant force is the square root of (56.6^2 + 88.6^2) N.

b) Direction of the resultant force:
To find the direction of the resultant force, we can use trigonometry. We can calculate the angle using the inverse tangent function (tan^-1).

Direction angle (θ) = tan^-1(FJenny/FSue)

Therefore, the direction of the resultant force is the angle whose tangent is the ratio of Jenny's force to Sue's force.

Now you can plug in the values into the formulas to find the answers to both parts of the question.