An escalator 14 m long is carrying a 70-kg person from one floor to another 8 m higher. The escalator has a speed of 1.0m/s. How much work does the escalator do in carrying the person to the top?

work: mass*g*height=mass*g*14*8

What do I put my answers in? So the anwser will be 14*8??

To calculate the work done by the escalator in carrying the person to the top, we need to find the change in potential energy.

The potential energy is given by the formula:
Potential Energy = mass * acceleration due to gravity * height

The mass of the person is 70 kg, the acceleration due to gravity is approximately 9.8 m/s², and the height is 8 m.

Potential Energy = 70 kg * 9.8 m/s² * 8 m
= 5,440 J

Therefore, the work done by the escalator in carrying the person to the top is 5,440 Joules.

To determine the amount of work done by the escalator in carrying the person to the top, we need to calculate the change in potential energy of the person.

The work done is given by the formula:

Work = Force x Distance

In this case, the force can be calculated using the mass and the acceleration due to gravity, which is approximately 9.8 m/s^2. The formula for force is:

Force = mass x acceleration due to gravity

Now, let's calculate the force:

Force = 70 kg x 9.8 m/s^2 = 686 N

Since the escalator is moving at a constant speed, the force applied by the escalator is equal in magnitude but opposite in direction to the force of gravity. Therefore, we can say that the net force acting on the person is zero.

Now, we can calculate the work done by the escalator:

Work = Force x Distance

Work = 0 N x 14 m

Since the net force acting on the person is zero, the work done by the escalator in carrying the person to the top is zero.

So, the escalator does not do any work in carrying the person to the top.