Calculate the amount of heat required to heat a 3.8 gold bar from 30 to 67. Specific heat capacity of gold is 0.128 .
A gold ring weighing 20 g at 25 °C is dropped into a beaker containing 15 g of boiling water. The final temperature of the water is 97 °C.
Recall that the heat capacity of water is 4.184 J/g °C.
To calculate the amount of heat required to heat a gold bar, we can use the equation:
Q = m * c * ΔT
Where:
Q is the amount of heat required
m is the mass of the gold bar
c is the specific heat capacity of gold
ΔT is the change in temperature
Given:
m = 3.8 grams
c = 0.128 J/g°C
ΔT = (67°C - 30°C) = 37°C
Now, let's substitute these values into the equation to calculate the heat required:
Q = (3.8 g) * (0.128 J/g°C) * (37°C)
Q = 18.6176 J
Therefore, the amount of heat required to heat a 3.8 grams gold bar from 30°C to 67°C is approximately 18.62 J.