Heyy is anybdy good at physics I am stuck on this question ...
... A camper van with a mass of 2500 kg has a maximum driving force of 2650 N.
The camper van drives along a straight road at a constant speed of 90 kilomatres per hour. At this speed, air resistance is 2000 N and the friction between the tyres and the road is 500 N.
What is the engine exerting?
PLease help !!!
Sure, I can help you with that! To find out what the engine is exerting, we need to consider the forces acting on the camper van.
The forces acting on the camper van are:
1. Driving force (exerted by the engine)
2. Air resistance
3. Friction between the tires and the road
The maximum driving force of the camper van is 2650 N, so we know that the driving force cannot exceed this value.
At a constant speed of 90 kilometers per hour, the camper van is not accelerating, which means the net force acting on it is zero. In other words, the sum of all the forces acting on the camper van is equal to zero.
So, to find the engine exertion, we need to add up the forces acting on the camper van and set it equal to zero:
Driving force - Air resistance - Friction = 0
Substituting the given values:
2650 N - 2000 N - 500 N = 0
Simplify the equation:
2650 N - (2000 N + 500 N) = 0
2650 N - 2500 N = 0
150 N = 0
Therefore, the engine is exerting a force of 150 N on the camper van.