Biochemistry

What is the pH after 5 mL of 0.1M NaOH has been added to 25 mL of 0.2M acetic acid?

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  1. millimoles NaOH = 5 mL x 0.1M = 0.5
    millimoles HAc = 25 mL x 0.2M = 5

    ...........NaOH + HAc ==> NaAc + H2O
    initial....0.5.....5.0.....0.......0
    change....-0.5....-0.5...+0.5...+0.5
    equil.......0.....4.5......0.5....0.5

    Substitute into the Henderson-Hasselbalch equation and solve for pH.

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