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Heat energy is released when anhydrous calcium chloride is dissolved in water.
CaCl2 (s) ¡æ CaCl2 (aq) + 83 kJ

Calculate the final temperature when 0.01 mol of calcium chloride is dissolved into 100 mL of water initially at a temperature of 18.0 degree celsius.

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  1. So how much heat is involved? That is 0.01 mole x 83 kJ/mol = 0.83 kJ or 830 J.
    830 = mass H2O x specific heat H2O x (Tfinal-Tinitial).
    Solve for Tfinal.

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