3/8x + 16 = 9/8x - 20

what is x ? please help!!!!

Joshua, Jack, Emmy -- you must be having an identity crisis.

Please use the same name for your posts.

im sorry i wont do that again

Multiply both sides by 8x.

3 + 128x = 9 - 160x

Add 160x and subtract 3 from both sides.

288x = 6

Divide both sides by 288.

To solve the equation 3/8x + 16 = 9/8x - 20 and find the value of x, we need to isolate the variable on one side of the equation. Here's how you can do that step by step:

1. Start by getting rid of the fractions by multiplying all terms in the equation by the least common denominator (LCD) of the denominators, which in this case is 8. This will result in integers instead of fractions.
- Multiply 8 by 3/8x to get (8)(3/8) * x = 3x
- Multiply 8 by 16 to get (8)(16) = 128
- Multiply 8 by 9/8x to get (8)(9/8) * x = 9x
- Multiply 8 by -20 to get (8)(-20) = -160

Now the equation becomes: 3x + 128 = 9x - 160

2. Next, let's gather the x terms on one side of the equation. You can do this by subtracting 3x from both sides:
3x + 128 - 3x = 9x - 3x -160
128 = 6x - 160

3. To isolate the variable term, we can add 160 to both sides of the equation:
128 + 160 = 6x - 160 + 160
288 = 6x

4. Finally, to solve for x, divide both sides of the equation by 6:
288 / 6 = (6x) / 6
48 = x

Therefore, the solution to the equation 3/8x + 16 = 9/8x - 20 is x = 48.