Find an expression for the function f(x) whose graph is given by the top half of the circle(x-3)^2 + y^2 = 121.

f(x) = ????

mATHS is Fu n

To find an expression for the function f(x) whose graph is the top half of the circle, we can start by rearranging the equation of the circle to solve for y.

Given: (x - 3)^2 + y^2 = 121

Subtracting (x - 3)^2 from both sides:
y^2 = 121 - (x - 3)^2

Now, taking the square root of both sides, we get:
y = ±√(121 - (x - 3)^2)

Since we are interested in the top half of the circle, we take the positive square root:
f(x) = √(121 - (x - 3)^2)

Hence, the expression for the function f(x) whose graph is the top half of the circle is f(x) = √(121 - (x - 3)^2).