A baby sitter pushing a stroller starts from
rest and accelerates uniformly at a rate of
0.511 m/s
2
.
What is the velocity of the stroller after it
has traveled 5.38 m?
Answer in units of m/s
Vf^2=2ad solve for Vf
.511m/s
To find the velocity of the stroller after it has traveled a certain distance, you can use the equation of motion:
v^2 = u^2 + 2as
Where:
v is the final velocity
u is the initial velocity (which is 0 m/s since the stroller starts from rest)
a is the acceleration (0.511 m/s^2 in this case)
s is the distance traveled (5.38 m)
Since the initial velocity is 0 m/s, the equation simplifies to:
v^2 = 2as
You can rearrange the equation to solve for v:
v = √(2as)
Substituting the given values:
v = √(2 * 0.511 m/s^2 * 5.38 m)
Calculating this, we get:
v ≈ √(5.51 m^2/s^2)
Finally, taking the square root of 5.51 m^2/s^2, we find:
v ≈ 2.35 m/s
Therefore, the velocity of the stroller after it has traveled 5.38 m is approximately 2.35 m/s.