A number has more tens than ones, but the digit in the tens place is less than 4. The value of the ones digit is less than 3. What are the possible numbers?
I'll be glad to check your answer.
so 10.
or 20,21
or 30,31,32
To find the possible numbers that satisfy the given conditions, we can systematically go through the options. Let's consider each digit separately.
First, let's consider the tens digit. We know that the digit in the tens place is less than 4 and that the number has more tens than ones. Since there are only four options (0, 1, 2, 3) for a digit less than 4, we can consider these options one by one.
If the tens digit is 0, then the ones digit must be less than 3. Therefore, these numbers could be 01, 02, or 03.
If the tens digit is 1, then the ones digit must also be less than 3. These numbers could be 10, 12, or 13.
If the tens digit is 2, then the ones digit must be less than 2 (it cannot be 3 because it needs to be less than 3). These numbers could be 20 or 21.
If the tens digit is 3, then the ones digit must be less than 1 (it cannot be 3 because it needs to be less than 3). Therefore, the only possibility is 30.
So, the possible numbers that satisfy the given conditions are: 01, 02, 03, 10, 12, 13, 20, 21, and 30.