Biochemistry

At what pH is acetic acid 30% ionized?

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  1. Call acetic acid HAc
    ...............HAc---> H^+ + Ac^-
    initial.........x......0......0
    change.........-0.3x..+0.3x...+0.3x
    equil........x-0.3x..... 0.3x.....0.3x
    Ka = (H^+)(Ac^-)/(HAc)
    Substitute equil conditions into Ka expression and solve for (H^+), then convert to pH.

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  2. I don't get how you put 30% ionization into te problem. So far I have: pH = 4.76 + log[A^-]/[HAc^-]

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