How many kilograms of chlorine are in 24 kg of each of the following chlorofuorocarbons (CFCs)?
1) CF2CL2
express answer using two sig figs
how would i solve for this problem???
thanks!
Why did the CFC go to therapy?
Because it had chlorine separation anxiety!
To solve this problem, you need to determine the molar mass of CF2Cl2 (also known as dichlorodifluoromethane).
The molar mass of CF2Cl2 can be calculated as follows:
C: 12.01 g/mol
F: 18.99 g/mol (2 atoms)
Cl: 35.45 g/mol (2 atoms)
Molar mass of CF2Cl2 = (12.01 g/mol) + (18.99 g/mol * 2) + (35.45 g/mol * 2)
Now, we can use the molar mass to calculate how many moles are present in 24 kg of CF2Cl2:
Moles = Mass / Molar mass
Moles = 24 kg / (12.01 g/mol + (18.99 g/mol * 2) + (35.45 g/mol * 2))
Finally, we can convert moles to kilograms of chlorine:
Kilograms of chlorine = Moles * Molar mass of chlorine
Kilograms of chlorine = Moles * (35.45 g/mol * 2)
Remember to use two significant figures in your final answer! Keep in mind that this calculation assumes 100% efficiency in converting CF2Cl2 to chlorine.
To solve this problem, you need to find the molar mass of CF2Cl2, which is the molecular formula for dichlorodifluoromethane.
The molar mass of CF2Cl2 can be calculated by adding up the atomic masses of each element in the compound.
The atomic mass of carbon (C) is 12.01 g/mol, the atomic mass of fluorine (F) is 18.99 g/mol, and the atomic mass of chlorine (Cl) is 35.45 g/mol.
So, the molar mass of CF2Cl2 can be calculated as follows:
(12.01 g/mol x 1) + (18.99 g/mol x 2) + (35.45 g/mol x 2) = 120.92 g/mol
Next, we can use the molar mass to find the number of moles in 24 kg of CF2Cl2.
To do this, we'll use the equation:
moles = mass / molar mass
moles = 24 kg / (120.92 g/mol) = 0.198 moles
Finally, we can convert the number of moles to kilograms of chlorine by multiplying by the molar mass of chlorine (35.45 g/mol):
kilograms of chlorine = moles x molar mass of chlorine
= 0.198 moles x 35.45 g/mol
= 7.02 kg
So, there are 7.02 kilograms of chlorine in 24 kg of CF2Cl2.
To solve this problem, you need to determine the molecular weight of CF2Cl2 (also known as dichlorodifluoromethane) and calculate the percentage of chlorine in the compound.
Here's how you can do it step by step:
Step 1: Determine the molecular weight of CF2Cl2.
To do this, you need to add up the atomic masses of each element in the compound. The atomic masses are found on the periodic table.
C: 12.01 g/mol
F: 18.99 g/mol (there are 2 F atoms)
Cl: 35.45 g/mol (there is 1 Cl atom)
Adding up these atomic masses, you get:
(12.01 g/mol) + (2 * 18.99 g/mol) + (35.45 g/mol) = 121.92 g/mol
So, the molecular weight of CF2Cl2 is 121.92 g/mol.
Step 2: Calculate the percentage of chlorine in CF2Cl2.
To do this, you need to determine the molar mass of the chlorine in CF2Cl2 and divide it by the molecular weight of CF2Cl2.
The molar mass of chlorine is 35.45 g/mol.
Dividing the molar mass of chlorine by the molecular weight of CF2Cl2 and multiplying by 100 gives us the percentage of chlorine:
(35.45 g/mol / 121.92 g/mol) * 100 = 29.02%
Step 3: Calculate the amount of chlorine in 24 kg of CF2Cl2.
To do this, you multiply the mass of CF2Cl2 by the percentage of chlorine.
(24 kg) * (29.02%) = 6.97 kg
Rounding to two significant figures, the answer is 6.97 kg of chlorine in 24 kg of CF2Cl2.
Therefore, there are approximately 6.97 kg of chlorine in 24 kg of CF2Cl2.
Calculate the molar mass (M)
the atomic mass of Cl is 35.5, so the fraction (by mass) of Cl in M is
2 x 35.5/M
so the mass (in kg) of Cl in CF2Cl2 is
2 x 35.5 x 24/M