math

a farmer wishes to enclose a rectangular region with 210 meters of fencing in such a way that the length is twice the width and the region is divided into two equal parts. what length and width should be used?

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  1. Width = X-meters.
    Length = 2X-metes.
    Divider = 2X-meters.

    2*x + 2*2x + 2x = 210m,
    2x + 4x + 2x = 210,
    8x = 210,

    X = 26.25m. = Width.
    2X = 2*26.25 = 52.5m. = Length.
    2X = 52.5 = Divider.

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  2. 26.25 is the width and the length is 52.25

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  3. x=width(since the width has three sections, left side, middle and right side, it becomes 3x)
    2x=length
    so equation is:

    2*2x(upper and lower lengths)+3x(left side, middle and right side)=210

    2*2x+3x=210
    4x+3x=210
    7x=210
    x=30
    2x=60
    so the length is 60m and the width is 30m.

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