geometry

if x squared equals 47 then what is the aproximate value of x

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  1. well to figure out what the answer is. you first set the equation which is x^2=47 after so to find out what x is. you have to isolate it. so to do that you have to get rid of the exponent 2 by square rooting both sides. thus leading it to be x=6.8556546. so to find the approximate i guess you round or such. be in mind that i am in eigth grade taking the geometry honors course this year

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  2. http://www.google.com/#pq=res%2F342&hl=en&sugexp=bvec&cp=14&gs_id=4f&xhr=t&q=square+root+47&pf=p&sclient=psy&source=hp&pbx=1&oq=square+root+47&aq=f&aqi=&aql=&gs_sm=&gs_upl=&bav=on.2,or.r_gc.r_pw.&fp=b7e6040383bebbf&biw=853&bih=544

  3. 4xt15=

    Give me answer

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