# geometry

if x squared equals 47 then what is the aproximate value of x

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1. well to figure out what the answer is. you first set the equation which is x^2=47 after so to find out what x is. you have to isolate it. so to do that you have to get rid of the exponent 2 by square rooting both sides. thus leading it to be x=6.8556546. so to find the approximate i guess you round or such. be in mind that i am in eigth grade taking the geometry honors course this year

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3. 4xt15=

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