if x squared equals 47 then what is the aproximate value of x
well to figure out what the answer is. you first set the equation which is x^2=47 after so to find out what x is. you have to isolate it. so to do that you have to get rid of the exponent 2 by square rooting both sides. thus leading it to be x=6.8556546. so to find the approximate i guess you round or such. be in mind that i am in eigth grade taking the geometry honors course this year
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To find the approximate value of x when x^2 equals 47, you can take the square root of both sides of the equation. However, it is important to note that there are two possible solutions for x, a positive and a negative value.
Using a calculator or a math software, you can find the approximate value of x by taking the square root of 47. The square root of 47 is approximately 6.8556546004.
So, the approximate values for x are x ≈ 6.8556546004 and x ≈ -6.8556546004.
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