Suppose that a NASCAR race car is moving to the right with a constant velocity of +92 m/s. What is the average acceleration of the car? (b) Twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed. What is the average acceleration of the car?

constant velocity means zero acceleration.

average acceleration= 2*92/12 m/s^2 in the direction to the left.

To find the average acceleration of an object, you need to know the change in velocity and the time it takes for that change to occur.

In the first scenario, the car is moving to the right with a constant velocity of +92 m/s. Since the velocity is constant, there is no change in velocity, and therefore the average acceleration is zero.

Now, moving on to the second scenario, where the car is halfway around the track and traveling in the opposite direction with the same speed. In this case, the change in velocity is from +92 m/s to -92 m/s (negative because it's in the opposite direction) in a time interval of twelve seconds.

To calculate the change in velocity, subtract the initial velocity from the final velocity:

Change in velocity = Final velocity - Initial velocity
Change in velocity = (-92 m/s) - (+92 m/s)
Change in velocity = -184 m/s

Now, divide the change in velocity by the time interval to find the average acceleration:

Average acceleration = Change in velocity / Time interval
Average acceleration = (-184 m/s) / (12 s)
Average acceleration ≈ -15.33 m/s²

So, in the second scenario, the average acceleration of the car is approximately -15.33 m/s². The negative sign indicates that the car is slowing down in the opposite direction.

To find the average acceleration of the car, we need to calculate the change in velocity and divide it by the change in time.

(a) The car is moving with a constant velocity of +92 m/s, which means that its velocity is not changing. Therefore, the change in velocity is zero, and the average acceleration is also zero:
Average acceleration (a) = change in velocity / change in time = 0 / t = 0 m/s²

(b) Twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed.

Since the car is traveling in the opposite direction, its velocity will be negative. The change in velocity will be the difference between the initial velocity (+92 m/s) and the final velocity (-92 m/s), which is:
Change in velocity = -92 m/s - (+92 m/s) = -184 m/s

The change in time is 12 seconds.

Now, we can calculate the average acceleration:
Average acceleration (a) = change in velocity / change in time = -184 m/s / 12 s ≈ -15.3 m/s²

Therefore, the average acceleration of the car is approximately -15.3 m/s².