A helicopter is ascending (moving upwards) at a constant velocity of 8 m/s. At a height of 90m, a passenger opens a window and drops a package to the ground below. How long does it take the package to hit the ground and how fast is it moving just before impact?
what was it about my previous response did you not understand?
calculate the magnetude of all the forces acting on the cabinet
To find out how long it takes for the package to hit the ground, we can use the formula to calculate the time it takes for an object to fall:
t = √(2h / g)
Where:
t is the time
h is the height
g is the acceleration due to gravity (approximately 9.8 m/s^2)
Plugging in the values for the height, we get:
t = √(2 * 90 / 9.8) = √(180 / 9.8) = √(18.367) ≈ 4.28 seconds
Therefore, it will take approximately 4.28 seconds for the package to hit the ground.
To find out how fast the package is moving just before impact, we can use the formula to calculate the final velocity of an object in freefall:
v = gt
Where:
v is the final velocity
g is the acceleration due to gravity
t is the time
Plugging in the values, we get:
v = 9.8 * 4.28 ≈ 41.944 m/s
Therefore, the package will be moving at approximately 41.944 m/s just before impact.