f(x)=-(x-1/2)^2(x+1)
How to find the y-intercept of the function?
f(0)=(0-1/2)^2(0+1)
post it.
To find the y-intercept of a function, you need to determine the value of the function when x is equal to 0. In other words, you'll need to find f(0).
In this case, the given function is f(x) = -(x - 1/2)^2(x + 1). To find the y-intercept, substitute x = 0 into the function:
f(0) = -((0) - 1/2)^2((0) + 1)
= -(−1/2)^2(1)
= -(1/4)(1)
= -1/4
Therefore, the y-intercept of the function f(x) = -(x - 1/2)^2(x + 1) is -1/4.